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Derivatives and problems

Discussion in 'Exploring everything under the sun!!' started by espnfreak, September 29, 2002.

^^Searches ExplorerForum.com^^
  1. espnfreak

    espnfreak Well-Known Member

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    Hey how do i find the equatio of the tangent line to the given point
    y=2xe^x,(0,0)

    i got the derivative to be 2x(e^x)+2e^x


    my other prob
    differentiating f(x)=x/(x+c/x)
     
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  3. Bshmastr

    Bshmastr Active Member

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    1) Use the y=mx+b form for the equation of a line. Use the derivative eqation you got to find the slope at (0,0). That's "m". "b" is zero. It should be y=2x.

    2) Use the quotient rule for differentiation.
    Should be [(x+c/x)-x(x-c/x^2)] / (x+c/x)^2.
    And you'd better hope x does not equal zero.
     
  4. Robb

    Robb Explorer Addict

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    I think X = blue :D

    Robb
     






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