Front Wheel Bearings 150ft lbs ? | Ford Explorer Forums

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Front Wheel Bearings 150ft lbs ?

Skiperrrr

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I have a 1993, 4 wheel drive, Explorer. The Chiltons manual says that the outer front wheel bearings should be torqued to 150 ft lbs. My torque wrench only goes up to 140 ft lbs so I thought 150 ft lbs was a little excessive. Does anyone know the proper torque for the outer wheel bearing nut?
 



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Do yourself a favor

and make sure it's not "in. lbs" instead of "ft. lbs"
 






150 foot pounds is correct, and even that isn't tight enough. I hope your talking the locking nuts and not hte inner nut... the inner nut should be about 16 INCH pounds which is less then finger pressure. I hate that system for locking the hubs in place, but what are ya gonna do...
 






Inches , Footes, Whats the difference?

I read the manual the same way, Bearing itself is inch pounds I believe, but the outer wheel bearing nut is 150 ft lbs. My drivers side has loosened up and backed off too, with the warn manual hubs.
 






well you figure inch pounds and foot pounds is just like inches and feet... 16 inch pounds = 1 1/3 foot pounds. Not sure how they decided on 16 and not 17... :). Mine back off all the time, it sucks... and its hard getting it back to 150 too, Im only about 200 with a poor sense of balance and those nuts are getting chipped away bit by bit... ah well.
 






Tighten the inner nut against the outer bearing "snug", while turning the rotor, to help seat the bearings. Back off completetly, then tighten by hand (16 inch pounds or so). When seating the locking washer (with the tab that goes in the groove in the spindle), loosen the inner nut if necessary for the pin to line up in a hole in the washer. Then, tighten the lock nut to 150 ft-lbs.

Hopefully, the inner nut will not turn with the outer nut. If, as on mine, the spindle threads are worn, the tab will not inhibit the inner nut from turning. I need to replace my spindles.
 






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