5 Pin Relay Question

Ok, i have searched and searched......I have some lights I want hooked up to a 5 pin relay I have. I see conflicting posts on what pin to use for what.....

Ok...I have the usual 5 pin #'s:

30
87
87a
85
86

So....here is my theory on how it should be used.....

86 Ground
85 Switched power
87 Lights
87a...not used for now
30 +12v

Is that right? 85 and 86 have the diode in between them....and 86 is at the bottom of the diagram....

Thanks...

 

[Kadarom Douhrek]

Everything looks good.
Except 87a.
Right now when the relay is off you will have power flowing from 30 to 87a.
You could insulate it somehow until you get something to put on it, or you could switch 87 and 30.
Make 87 the 12V source and 30 the output.
The circuit will work the same, but 87a won't be charged at any time.

 

[Crankcase]

So, with my current setup....when I turn on the relay, power from 30 goes to both 87, and 87a?

 

[Kadarom Douhrek]

No, no, no.
There is a switch inside connected to pin 30 on one side.
Normally a spring holds the other end of the switch against pin 87a, connecting 30 and 87a.
When there is power flowing between 85 and 86 a coil charges creating an electromagnet and the switch is pulled from 87a to 87.

So, when there's no power to 85/86, 30 and 87a are connected.
When there is power 30 and 87 are connected.


By the switch's design it doesn't care which direction current flows.
That means you can either use the classic setup and have 30 the source with 87a the normally on output and 87 the normally off output.
Or, you can use 87 and/or 87a as source and 30 as output.

 

[Crankcase]

Ah...I see. thanks for the help.

I think I will hook it upo the classic way...with 87a left open for something else.....I can insulate it LOL

My crude drawing in paint: